1=0.025x^2+0.1

Solution for 1=0.025x^2+0.1 equation:

1=0.025x^2+0.1

We move all terms to the left:

1-(0.025x^2+0.1)=0

We get rid of parentheses

-0.025x^2-0.1+1=0

We add all the numbers together, and all the variables

-0.025x^2+0.9=0

a = -0.025; b = 0; c = +0.9;
Δ = b2-4ac
Δ = 02-4·(-0.025)·0.9
Δ = 0.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.09}}{2*-0.025}=\frac{0-\sqrt{0.09}}{-0.05}
=-\frac{\sqrt{}}{-0.05}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.09}}{2*-0.025}=\frac{0+\sqrt{0.09}}{-0.05}
=\frac{\sqrt{}}{-0.05}
$